Whakaoti i te 2-{2m+[2m-(2-2m)]}=2

$$2 - \{ 2 m + [ 2 m - ( 2 - 2 m ) ] \} = 2$$

Whakaoti mō m

$$m=\frac{1}{3}\approx 0.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te 2m me 2m, ka 4m.

$$2-\left(4m-\left(2-2m\right)\right)=2$$

Hei kimi i te tauaro o 2-2m, kimihia te tauaro o ia taurangi.

$$2-\left(4m-2-\left(-2m\right)\right)=2$$

Ko te tauaro o -2m ko 2m.

$$2-\left(4m-2+2m\right)=2$$

Pahekotia te 4m me 2m, ka 6m.

$$2-\left(6m-2\right)=2$$

Hei kimi i te tauaro o 6m-2, kimihia te tauaro o ia taurangi.

$$2-6m-\left(-2\right)=2$$

Ko te tauaro o -2 ko 2.

$$2-6m+2=2$$

Tāpirihia te 2 ki te 2, ka 4.

$$4-6m=2$$

Tangohia te 4 mai i ngā taha e rua.

$$-6m=2-4$$

Tangohia te 4 i te 2, ka -2.

$$-6m=-2$$

Whakawehea ngā taha e rua ki te -6.

$$m=\frac{-2}{-6}$$

Whakahekea te hautanga \frac{-2}{-6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$m=\frac{1}{3}$$