Whakaoti i te 2(n-5)+3n-1=2(n+3)-(n+1)

$$2 ( n - 5 ) + 3 n - 1 = 2 ( n + 3 ) - ( n + 1 )$$

Whakaoti mō n

$$n=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te n-5.

$$2n-10+3n-1=2\left(n+3\right)-\left(n+1\right)$$

Pahekotia te 2n me 3n, ka 5n.

$$5n-10-1=2\left(n+3\right)-\left(n+1\right)$$

Tangohia te 1 i te -10, ka -11.

$$5n-11=2\left(n+3\right)-\left(n+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te n+3.

$$5n-11=2n+6-\left(n+1\right)$$

Hei kimi i te tauaro o n+1, kimihia te tauaro o ia taurangi.

$$5n-11=2n+6-n-1$$

Pahekotia te 2n me -n, ka n.

$$5n-11=n+6-1$$

Tangohia te 1 i te 6, ka 5.

$$5n-11=n+5$$

Tangohia te n mai i ngā taha e rua.

$$5n-11-n=5$$

Pahekotia te 5n me -n, ka 4n.

$$4n-11=5$$

Me tāpiri te 11 ki ngā taha e rua.

$$4n=5+11$$

Tāpirihia te 5 ki te 11, ka 16.

$$4n=16$$

Whakawehea ngā taha e rua ki te 4.

$$n=\frac{16}{4}$$

Whakawehea te 16 ki te 4, kia riro ko 4.

$$n=4$$