Whakaoti i te 2(8x^2-3)=0

$$2 ( 8 x ^ { 2 } - 3 ) = 0$$

Whakaoti mō x

$$x=\frac{\sqrt{6}}{4}\approx 0.612372436$$

$$x=-\frac{\sqrt{6}}{4}\approx -0.612372436$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 2. Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$8x^{2}-3=0$$

Me tāpiri te 3 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$8x^{2}=3$$

Whakawehea ngā taha e rua ki te 8.

$$x^{2}=\frac{3}{8}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{6}}{4} x=-\frac{\sqrt{6}}{4}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 2. Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$8x^{2}-3=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 8 mō a, 0 mō b, me -3 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 8\left(-3\right)}}{2\times 8}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 8\left(-3\right)}}{2\times 8}$$

Whakareatia -4 ki te 8.

$$x=\frac{0±\sqrt{-32\left(-3\right)}}{2\times 8}$$

Whakareatia -32 ki te -3.

$$x=\frac{0±\sqrt{96}}{2\times 8}$$

Tuhia te pūtakerua o te 96.

$$x=\frac{0±4\sqrt{6}}{2\times 8}$$

Whakareatia 2 ki te 8.

$$x=\frac{0±4\sqrt{6}}{16}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{6}}{16} ina he tāpiri te ±.

$$x=\frac{\sqrt{6}}{4}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{6}}{16} ina he tango te ±.

$$x=-\frac{\sqrt{6}}{4}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{6}}{4} x=-\frac{\sqrt{6}}{4}$$