Whakaoti i te 2(11-40)=3-(5a+2)

$$2 ( 11 - 40 ) = 3 - ( 5 a + 2 )$$

Whakaoti mō a

$$a = \frac{59}{5} = 11\frac{4}{5} = 11.8$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 40 i te 11, ka -29.

$$2\left(-29\right)=3-\left(5a+2\right)$$

Whakareatia te 2 ki te -29, ka -58.

$$-58=3-\left(5a+2\right)$$

Hei kimi i te tauaro o 5a+2, kimihia te tauaro o ia taurangi.

$$-58=3-5a-2$$

Tangohia te 2 i te 3, ka 1.

$$-58=1-5a$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$1-5a=-58$$

Tangohia te 1 mai i ngā taha e rua.

$$-5a=-58-1$$

Tangohia te 1 i te -58, ka -59.

$$-5a=-59$$

Whakawehea ngā taha e rua ki te -5.

$$a=\frac{-59}{-5}$$

Ka taea te hautanga \frac{-59}{-5} te whakamāmā ki te \frac{59}{5} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$a=\frac{59}{5}$$