Whakaoti i te 2(x/4+4)-4(x/2+2)=8-2x

$$2 ( \frac { x } { 4 } + 4 ) - 4 ( \frac { x } { 2 } + 2 ) = 8 - 2 x$$

Whakaoti mō x

$$x=16$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 4, arā, te tauraro pātahi he tino iti rawa te kitea o 4,2.

$$8\left(\frac{x}{4}+4\right)-16\left(\frac{x}{2}+2\right)=32-8x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te \frac{x}{4}+4.

$$8\times \frac{x}{4}+32-16\left(\frac{x}{2}+2\right)=32-8x$$

Whakakorea atu te tauwehe pūnoa nui rawa 4 i roto i te 8 me te 4.

$$2x+32-16\left(\frac{x}{2}+2\right)=32-8x$$

Me tāpiri te 8x ki ngā taha e rua.

$$2x+32-16\left(\frac{x}{2}+2\right)+8x=32$$

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2\left(2x+32-16\left(\frac{x}{2}+2\right)\right)+16x=64$$

Whakareatia ngā taha e rua o te whārite ki te 2.

$$4\left(2x+32-16\left(\frac{x}{2}+2\right)\right)+32x=128$$

Whakamahia te āhuatanga tohatoha hei whakarea te -16 ki te \frac{x}{2}+2.

$$4\left(2x+32-16\times \frac{x}{2}-32\right)+32x=128$$

Whakakorea atu te tauwehe pūnoa nui rawa 2 i roto i te 16 me te 2.

$$4\left(2x+32-8x-32\right)+32x=128$$

Pahekotia te 2x me -8x, ka -6x.

$$4\left(-6x+32-32\right)+32x=128$$

Tangohia te 32 i te 32, ka 0.

$$4\left(-6\right)x+32x=128$$

Whakareatia te 4 ki te -6, ka -24.

$$-24x+32x=128$$

Pahekotia te -24x me 32x, ka 8x.

$$8x=128$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{128}{8}$$

Whakawehea te 128 ki te 8, kia riro ko 16.

$$x=16$$