Whakaoti i te 2(7/3-5/3y)+7y=12

$$2 ( \frac { 7 } { 3 } - \frac { 5 } { 3 } y ) + 7 y = 12$$

Whakaoti mō y

$$y=2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te \frac{7}{3}-\frac{5}{3}y.

$$2\times \frac{7}{3}+2\left(-\frac{5}{3}\right)y+7y=12$$

Tuhia te 2\times \frac{7}{3} hei hautanga kotahi.

$$\frac{2\times 7}{3}+2\left(-\frac{5}{3}\right)y+7y=12$$

Whakareatia te 2 ki te 7, ka 14.

$$\frac{14}{3}+2\left(-\frac{5}{3}\right)y+7y=12$$

Tuhia te 2\left(-\frac{5}{3}\right) hei hautanga kotahi.

$$\frac{14}{3}+\frac{2\left(-5\right)}{3}y+7y=12$$

Whakareatia te 2 ki te -5, ka -10.

$$\frac{14}{3}+\frac{-10}{3}y+7y=12$$

Ka taea te hautanga \frac{-10}{3} te tuhi anō ko -\frac{10}{3} mā te tango i te tohu tōraro.

$$\frac{14}{3}-\frac{10}{3}y+7y=12$$

Pahekotia te -\frac{10}{3}y me 7y, ka \frac{11}{3}y.

$$\frac{14}{3}+\frac{11}{3}y=12$$

Tangohia te \frac{14}{3} mai i ngā taha e rua.

$$\frac{11}{3}y=12-\frac{14}{3}$$

Me tahuri te 12 ki te hautau \frac{36}{3}.

$$\frac{11}{3}y=\frac{36}{3}-\frac{14}{3}$$

Tā te mea he rite te tauraro o \frac{36}{3} me \frac{14}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{11}{3}y=\frac{36-14}{3}$$

Tangohia te 14 i te 36, ka 22.

$$\frac{11}{3}y=\frac{22}{3}$$

Me whakarea ngā taha e rua ki te \frac{3}{11}, te tau utu o \frac{11}{3}.

$$y=\frac{22}{3}\times \frac{3}{11}$$

Me whakarea te \frac{22}{3} ki te \frac{3}{11} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$y=\frac{22\times 3}{3\times 11}$$

Me whakakore tahi te 3 i te taurunga me te tauraro.

$$y=\frac{22}{11}$$

Whakawehea te 22 ki te 11, kia riro ko 2.

$$y=2$$