Whakaoti i te 2x^2-x-1=x^2-5x-(-1-x^2)

$$2 { x }^{ 2 } -x-1= { x }^{ 2 } -5x-(-1- { x }^{ 2 } )$$

Whakaoti mō x

$$x=\frac{1}{2}=0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o -1-x^{2}, kimihia te tauaro o ia taurangi.

$$2x^{2}-x-1=x^{2}-5x+1+x^{2}$$

Pahekotia te x^{2} me x^{2}, ka 2x^{2}.

$$2x^{2}-x-1=2x^{2}-5x+1$$

Tangohia te 2x^{2} mai i ngā taha e rua.

$$2x^{2}-x-1-2x^{2}=-5x+1$$

Pahekotia te 2x^{2} me -2x^{2}, ka 0.

$$-x-1=-5x+1$$

Me tāpiri te 5x ki ngā taha e rua.

$$-x-1+5x=1$$

Pahekotia te -x me 5x, ka 4x.

$$4x-1=1$$

Me tāpiri te 1 ki ngā taha e rua.

$$4x=1+1$$

Tāpirihia te 1 ki te 1, ka 2.

$$4x=2$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{2}{4}$$

Whakahekea te hautanga \frac{2}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{1}{2}$$