Whakaoti i te 2x^2-8x+16=

$$2 { x }^{ 2 } -8x+16=$$

Tauwehe

$$2\left(x^{2}-4x+8\right)$$

Ngā Upane Otinga

Tauwehea te 2. Kāore te pūrau x^{2}-4x+8 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$2\left(x^{2}-4x+8\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$2x^{2}-8x+16=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 2\times 16}}{2\times 2}$$

Pūrua -8.

$$x=\frac{-\left(-8\right)±\sqrt{64-4\times 2\times 16}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{-\left(-8\right)±\sqrt{64-8\times 16}}{2\times 2}$$

Whakareatia -8 ki te 16.

$$x=\frac{-\left(-8\right)±\sqrt{64-128}}{2\times 2}$$

Tāpiri 64 ki te -128.

$$x=\frac{-\left(-8\right)±\sqrt{-64}}{2\times 2}$$

Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. Kāore e taea te pūrau pūrua te whakatauwehe.

$$2x^{2}-8x+16$$

Aromātai

$$2\left(x^{2}-4x+8\right)$$