Whakaoti i te 2x^2+32=6

$$2 { x }^{ 2 } +32=6$$

Whakaoti mō x (complex solution)

$$x=-\sqrt{13}i\approx -0-3.605551275i$$

$$x=\sqrt{13}i\approx 3.605551275i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 32 mai i ngā taha e rua.

$$2x^{2}=6-32$$

Tangohia te 32 i te 6, ka -26.

$$2x^{2}=-26$$

Whakawehea ngā taha e rua ki te 2.

$$x^{2}=\frac{-26}{2}$$

Whakawehea te -26 ki te 2, kia riro ko -13.

$$x^{2}=-13$$

Kua oti te whārite te whakatau.

$$x=\sqrt{13}i x=-\sqrt{13}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 6 mai i ngā taha e rua.

$$2x^{2}+32-6=0$$

Tangohia te 6 i te 32, ka 26.

$$2x^{2}+26=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 0 mō b, me 26 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\times 26}}{2\times 2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2\times 26}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8\times 26}}{2\times 2}$$

Whakareatia -8 ki te 26.

$$x=\frac{0±\sqrt{-208}}{2\times 2}$$

Tuhia te pūtakerua o te -208.

$$x=\frac{0±4\sqrt{13}i}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{0±4\sqrt{13}i}{4}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{13}i}{4} ina he tāpiri te ±.

$$x=\sqrt{13}i$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{13}i}{4} ina he tango te ±.

$$x=-\sqrt{13}i$$

Kua oti te whārite te whakatau.

$$x=\sqrt{13}i x=-\sqrt{13}i$$