Whakaoti i te 2*7^2n-98=0

$$2 \times 7 ^ { 2 n } - 98 = 0$$

Whakaoti mō n

$$n=1$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$2\times 7^{2n}-98=0$$

Me tāpiri 98 ki ngā taha e rua o te whārite.

$$2\times 7^{2n}=98$$

Whakawehea ngā taha e rua ki te 2.

$$7^{2n}=49$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(7^{2n})=\log(49)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$2n\log(7)=\log(49)$$

Whakawehea ngā taha e rua ki te \log(7).

$$2n=\frac{\log(49)}{\log(7)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2n=\log_{7}\left(49\right)$$

Whakawehea ngā taha e rua ki te 2.

$$n=\frac{2}{2}$$