Whakaoti i te 2*((4*2^2-1/5*2^5)-(4*0^2-1/5*0^2))-?/5=

$$2 \times ( ( 4 \times 2 ^ { 2 } - \frac { 1 } { 5 } \times 2 ^ { 5 } ) - ( 4 \times 0 ^ { 2 } - \frac { 1 } { 5 } \times 0 ^ { 2 } ) ) - \frac { ? } { 5 } =$$

Aromātai

$$19$$

Ngā Upane Otinga

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$2\left(4\times 4-\frac{1}{5}\times 2^{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Whakareatia te 4 ki te 4, ka 16.

$$2\left(16-\frac{1}{5}\times 2^{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Tātaihia te 2 mā te pū o 5, kia riro ko 32.

$$2\left(16-\frac{1}{5}\times 32-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Whakareatia te \frac{1}{5} ki te 32, ka \frac{32}{5}.

$$2\left(16-\frac{32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Me tahuri te 16 ki te hautau \frac{80}{5}.

$$2\left(\frac{80}{5}-\frac{32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Tā te mea he rite te tauraro o \frac{80}{5} me \frac{32}{5}, me tango rāua mā te tango i ō raua taurunga.

$$2\left(\frac{80-32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Tangohia te 32 i te 80, ka 48.

$$2\left(\frac{48}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$2\left(\frac{48}{5}-\left(4\times 0-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Whakareatia te 4 ki te 0, ka 0.

$$2\left(\frac{48}{5}-\left(0-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$2\left(\frac{48}{5}-\left(0-\frac{1}{5}\times 0\right)\right)-\frac{1}{5}$$

Whakareatia te \frac{1}{5} ki te 0, ka 0.

$$2\left(\frac{48}{5}-\left(0-0\right)\right)-\frac{1}{5}$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$2\left(\frac{48}{5}-0\right)-\frac{1}{5}$$

Tangohia te 0 i te \frac{48}{5}, ka \frac{48}{5}.

$$2\times \frac{48}{5}-\frac{1}{5}$$

Tuhia te 2\times \frac{48}{5} hei hautanga kotahi.

$$\frac{2\times 48}{5}-\frac{1}{5}$$

Whakareatia te 2 ki te 48, ka 96.

$$\frac{96}{5}-\frac{1}{5}$$

Tā te mea he rite te tauraro o \frac{96}{5} me \frac{1}{5}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{96-1}{5}$$

Tangohia te 1 i te 96, ka 95.

$$\frac{95}{5}$$

Whakawehea te 95 ki te 5, kia riro ko 19.

$$19$$

Tauwehe

$$19$$