Whakaoti i te 2sqrt{x}*2sqrt{x}

$$2 \sqrt{ x } \times 2 \sqrt{ x }$$

Aromātai

$$4x$$

Ngā Upane Otinga

Whakareatia te \sqrt{x} ki te \sqrt{x}, ka \left(\sqrt{x}\right)^{2}.

$$2\times 2\left(\sqrt{x}\right)^{2}$$

Whakareatia te 2 ki te 2, ka 4.

$$4\left(\sqrt{x}\right)^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$4x$$

Kimi Pārōnaki e ai ki x

$$4$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Whakareatia te \sqrt{x} ki te \sqrt{x}, ka \left(\sqrt{x}\right)^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2\times 2\left(\sqrt{x}\right)^{2})$$

Whakareatia te 2 ki te 2, ka 4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4\left(\sqrt{x}\right)^{2})$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$4x^{1-1}$$

Tango 1 mai i 1.

$$4x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$4\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$4$$