Whakaoti i te 2sqrt{2-7x}=sqrt{-36x}

$$2 \sqrt{ 2-7x } = \sqrt{ -36x }$$

Whakaoti mō x

$$x=-1$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(2\sqrt{2-7x}\right)^{2}=\left(\sqrt{-36x}\right)^{2}$$

Whakarohaina te \left(2\sqrt{2-7x}\right)^{2}.

$$2^{2}\left(\sqrt{2-7x}\right)^{2}=\left(\sqrt{-36x}\right)^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$4\left(\sqrt{2-7x}\right)^{2}=\left(\sqrt{-36x}\right)^{2}$$

Tātaihia te \sqrt{2-7x} mā te pū o 2, kia riro ko 2-7x.

$$4\left(2-7x\right)=\left(\sqrt{-36x}\right)^{2}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 2-7x.

$$8-28x=\left(\sqrt{-36x}\right)^{2}$$

Tātaihia te \sqrt{-36x} mā te pū o 2, kia riro ko -36x.

$$8-28x=-36x$$

Me tāpiri te 36x ki ngā taha e rua.

$$8-28x+36x=0$$

Pahekotia te -28x me 36x, ka 8x.

$$8+8x=0$$

Tangohia te 8 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$8x=-8$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{-8}{8}$$

Whakawehea te -8 ki te 8, kia riro ko -1.

$$x=-1$$

Whakakapia te -1 mō te x i te whārite 2\sqrt{2-7x}=\sqrt{-36x}.

$$2\sqrt{2-7\left(-1\right)}=\sqrt{-36\left(-1\right)}$$

Whakarūnātia. Ko te uara x=-1 kua ngata te whārite.

$$6=6$$

Ko te whārite 2\sqrt{2-7x}=\sqrt{-36x} he rongoā ahurei.

$$x=-1$$