Whakaoti i te 2sqrt{12}+4sqrt{18}divsqrt{3}

$$2 \sqrt{ 12 } +4 \sqrt{ 18 } \div \sqrt{ 3 }$$

Aromātai

$$4\left(\sqrt{3}+\sqrt{6}\right)\approx 16.726162201$$

Ngā Upane Otinga

Tauwehea te 12=2^{2}\times 3. Tuhia anō te pūtake rua o te hua \sqrt{2^{2}\times 3} hei hua o ngā pūtake rua \sqrt{2^{2}}\sqrt{3}. Tuhia te pūtakerua o te 2^{2}.

$$2\times 2\sqrt{3}+\frac{4\sqrt{18}}{\sqrt{3}}$$

Whakareatia te 2 ki te 2, ka 4.

$$4\sqrt{3}+\frac{4\sqrt{18}}{\sqrt{3}}$$

Tauwehea te 18=3^{2}\times 2. Tuhia anō te pūtake rua o te hua \sqrt{3^{2}\times 2} hei hua o ngā pūtake rua \sqrt{3^{2}}\sqrt{2}. Tuhia te pūtakerua o te 3^{2}.

$$4\sqrt{3}+\frac{4\times 3\sqrt{2}}{\sqrt{3}}$$

Whakareatia te 4 ki te 3, ka 12.

$$4\sqrt{3}+\frac{12\sqrt{2}}{\sqrt{3}}$$

Whakangāwaritia te tauraro o \frac{12\sqrt{2}}{\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$4\sqrt{3}+\frac{12\sqrt{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$4\sqrt{3}+\frac{12\sqrt{2}\sqrt{3}}{3}$$

Hei whakarea \sqrt{2} me \sqrt{3}, whakareatia ngā tau i raro i te pūtake rua.

$$4\sqrt{3}+\frac{12\sqrt{6}}{3}$$

Whakawehea te 12\sqrt{6} ki te 3, kia riro ko 4\sqrt{6}.

$$4\sqrt{3}+4\sqrt{6}$$

Tauwehe

$$4 {(\sqrt{3} + \sqrt{6})} = 16.726162201$$