Whakaoti i te 2sqrt{3}+2i=xe^2y

$$2 \sqrt { 3 } + 2 i = x e ^ { 2 y }$$

Whakaoti mō x

$$x=\frac{2\left(\sqrt{3}+i\right)}{e^{2y}}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$xe^{2y}=2\sqrt{3}+2i$$

He hanga arowhānui tō te whārite.

$$e^{2y}x=2\sqrt{3}+2i$$

Whakawehea ngā taha e rua ki te e^{2y}.

$$\frac{e^{2y}x}{e^{2y}}=\frac{2\sqrt{3}+2i}{e^{2y}}$$

Mā te whakawehe ki te e^{2y} ka wetekia te whakareanga ki te e^{2y}.

$$x=\frac{2\sqrt{3}+2i}{e^{2y}}$$

Whakawehe 2\sqrt{3}+2i ki te e^{2y}.

$$x=\frac{2\left(\sqrt{3}+i\right)}{e^{2y}}$$

Whakaoti mō y

$$y=\frac{\ln(\frac{\sqrt{3}+i}{x})+\ln(2)}{2}+\pi n_{1}i$$

$$n_{1}\in \mathrm{Z}$$

$$x\neq 0$$