Whakaoti i te 2piR^2H=27pir^2(10)

$$2 \pi R ^ { 2 } H = 27 \pi r ^ { 2 } ( 10 )$$

Whakaoti mō H

$$\left\{\begin{matrix}H=135\times \left(\frac{r}{R}\right)^{2}\text{, }&R\neq 0\\H\in \mathrm{R}\text{, }&r=0\text{ and }R=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakakore te \pi ki ngā taha e rua.

$$2R^{2}H=27r^{2}\times 10$$

Whakareatia te 27 ki te 10, ka 270.

$$2R^{2}H=270r^{2}$$

Whakawehea ngā taha e rua ki te 2R^{2}.

$$\frac{2R^{2}H}{2R^{2}}=\frac{270r^{2}}{2R^{2}}$$

Mā te whakawehe ki te 2R^{2} ka wetekia te whakareanga ki te 2R^{2}.

$$H=\frac{270r^{2}}{2R^{2}}$$

Whakawehe 270r^{2} ki te 2R^{2}.

$$H=\frac{135r^{2}}{R^{2}}$$

Whakaoti mō R

$$\left\{\begin{matrix}R=3\sqrt{\frac{15}{H}}r\text{; }R=-3\sqrt{\frac{15}{H}}r\text{, }&H>0\\R=0\text{, }&r=0\text{ and }H\neq 0\\R\in \mathrm{R}\text{, }&r=0\text{ and }H=0\end{matrix}\right.$$