Whakaoti i te 2pi(R-b)=2piR+1

$$2 \pi ( R - b ) = 2 \pi R + 1$$

Whakaoti mō b

$$b = -\frac{1}{2 \pi} = -0.15915494309189535$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2\pi ki te R-b.

$$2\pi R-2\pi b=2\pi R+1$$

Tangohia te 2\pi R mai i ngā taha e rua.

$$-2\pi b=2\pi R+1-2\pi R$$

Pahekotia te 2\pi R me -2\pi R, ka 0.

$$-2\pi b=1$$

He hanga arowhānui tō te whārite.

$$\left(-2\pi \right)b=1$$

Whakawehea ngā taha e rua ki te -2\pi .

$$\frac{\left(-2\pi \right)b}{-2\pi }=\frac{1}{-2\pi }$$

Mā te whakawehe ki te -2\pi ka wetekia te whakareanga ki te -2\pi .

$$b=\frac{1}{-2\pi }$$

Whakawehe 1 ki te -2\pi .

$$b=-\frac{1}{2\pi }$$

Whakaoti mō R (complex solution)

$$R\in \mathrm{C}$$

$$b = -\frac{1}{2 \pi} = -0.15915494309189535$$

Whakaoti mō R

$$R\in \mathrm{R}$$

$$b = -\frac{1}{2 \pi} = -0.15915494309189535$$