Whakaoti i te 21-i/2+i=

$$2 \frac { 1 - i } { 2 + i } =$$

Aromātai

$$\frac{2}{5}-\frac{6}{5}i=0.4-1.2i$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1-i}{2+i} ki te haumi hiato o te tauraro, 2-i.

$$2\times \frac{\left(1-i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$2\times \frac{\left(1-i\right)\left(2-i\right)}{2^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$2\times \frac{\left(1-i\right)\left(2-i\right)}{5}$$

Me whakarea ngā tau matatini 1-i me 2-i pēnā i te whakarea huarua.

$$2\times \frac{1\times 2+1\left(-i\right)-i\times 2-\left(-i^{2}\right)}{5}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$2\times \frac{1\times 2+1\left(-i\right)-i\times 2-\left(-\left(-1\right)\right)}{5}$$

Mahia ngā whakarea i roto o 1\times 2+1\left(-i\right)-i\times 2-\left(-\left(-1\right)\right).

$$2\times \frac{2-i-2i-1}{5}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 2-i-2i-1.

$$2\times \frac{2-1+\left(-1-2\right)i}{5}$$

Mahia ngā tāpiri i roto o 2-1+\left(-1-2\right)i.

$$2\times \frac{1-3i}{5}$$

Whakawehea te 1-3i ki te 5, kia riro ko \frac{1}{5}-\frac{3}{5}i.

$$2\left(\frac{1}{5}-\frac{3}{5}i\right)$$

Whakareatia 2 ki te \frac{1}{5}-\frac{3}{5}i.

$$2\times \frac{1}{5}+2\times \left(-\frac{3}{5}i\right)$$

Mahia ngā whakarea.

$$\frac{2}{5}-\frac{6}{5}i$$

Wāhi Tūturu

$$\frac{2}{5} = 0.4$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1-i}{2+i} ki te haumi hiato o te tauraro, 2-i.

$$Re(2\times \frac{\left(1-i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(2\times \frac{\left(1-i\right)\left(2-i\right)}{2^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(2\times \frac{\left(1-i\right)\left(2-i\right)}{5})$$

Me whakarea ngā tau matatini 1-i me 2-i pēnā i te whakarea huarua.

$$Re(2\times \frac{1\times 2+1\left(-i\right)-i\times 2-\left(-i^{2}\right)}{5})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(2\times \frac{1\times 2+1\left(-i\right)-i\times 2-\left(-\left(-1\right)\right)}{5})$$

Mahia ngā whakarea i roto o 1\times 2+1\left(-i\right)-i\times 2-\left(-\left(-1\right)\right).

$$Re(2\times \frac{2-i-2i-1}{5})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 2-i-2i-1.

$$Re(2\times \frac{2-1+\left(-1-2\right)i}{5})$$

Mahia ngā tāpiri i roto o 2-1+\left(-1-2\right)i.

$$Re(2\times \frac{1-3i}{5})$$

Whakawehea te 1-3i ki te 5, kia riro ko \frac{1}{5}-\frac{3}{5}i.

$$Re(2\left(\frac{1}{5}-\frac{3}{5}i\right))$$

Whakareatia 2 ki te \frac{1}{5}-\frac{3}{5}i.

$$Re(2\times \frac{1}{5}+2\times \left(-\frac{3}{5}i\right))$$

Mahia ngā whakarea i roto o 2\times \frac{1}{5}+2\times \left(-\frac{3}{5}i\right).

$$Re(\frac{2}{5}-\frac{6}{5}i)$$

Ko te wāhi tūturu o \frac{2}{5}-\frac{6}{5}i ko \frac{2}{5}.

$$\frac{2}{5}$$