Whakaoti i te 2*(x-1)^2=c-4x

$$2 \cdot ( x - 1 ) ^ { 2 } = c - 4 x$$

Whakaoti mō c

$$c=2\left(x^{2}+1\right)$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-1\right)^{2}.

$$2\left(x^{2}-2x+1\right)=c-4x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x^{2}-2x+1.

$$2x^{2}-4x+2=c-4x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$c-4x=2x^{2}-4x+2$$

Me tāpiri te 4x ki ngā taha e rua.

$$c=2x^{2}-4x+2+4x$$

Pahekotia te -4x me 4x, ka 0.

$$c=2x^{2}+2$$

Whakaoti mō x (complex solution)

$$x=-\frac{\sqrt{2\left(c-2\right)}}{2}$$

$$x=\frac{\sqrt{2\left(c-2\right)}}{2}$$

Whakaoti mō x

$$x=\frac{\sqrt{2\left(c-2\right)}}{2}$$

$$x=-\frac{\sqrt{2\left(c-2\right)}}{2}\text{, }c\geq 2$$