Whakaoti i te 2*(x+4)-3*(x+1)^2=x*(6-3x)

$$2 \cdot ( x + 4 ) - 3 \cdot ( x + 1 ) ^ { 2 } = x \cdot ( 6 - 3 x )$$

Whakaoti mō x

$$x=\frac{1}{2}=0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x+4.

$$2x+8-3\left(x+1\right)^{2}=x\left(6-3x\right)$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$2x+8-3\left(x^{2}+2x+1\right)=x\left(6-3x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x^{2}+2x+1.

$$2x+8-3x^{2}-6x-3=x\left(6-3x\right)$$

Pahekotia te 2x me -6x, ka -4x.

$$-4x+8-3x^{2}-3=x\left(6-3x\right)$$

Tangohia te 3 i te 8, ka 5.

$$-4x+5-3x^{2}=x\left(6-3x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 6-3x.

$$-4x+5-3x^{2}=6x-3x^{2}$$

Tangohia te 6x mai i ngā taha e rua.

$$-4x+5-3x^{2}-6x=-3x^{2}$$

Pahekotia te -4x me -6x, ka -10x.

$$-10x+5-3x^{2}=-3x^{2}$$

Me tāpiri te 3x^{2} ki ngā taha e rua.

$$-10x+5-3x^{2}+3x^{2}=0$$

Pahekotia te -3x^{2} me 3x^{2}, ka 0.

$$-10x+5=0$$

Tangohia te 5 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-10x=-5$$

Whakawehea ngā taha e rua ki te -10.

$$x=\frac{-5}{-10}$$

Whakahekea te hautanga \frac{-5}{-10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -5.

$$x=\frac{1}{2}$$