Whakaoti i te 2^x=1/32

$$2 ^ { x } = \frac { 1 } { 32 }$$

Whakaoti mō x

$$x=-5$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$2^{x}=\frac{1}{32}$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(2^{x})=\log(\frac{1}{32})$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$x\log(2)=\log(\frac{1}{32})$$

Whakawehea ngā taha e rua ki te \log(2).

$$x=\frac{\log(\frac{1}{32})}{\log(2)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{2}\left(\frac{1}{32}\right)$$

Whakaoti mō x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(2)}-5$$

$$n_{1}\in \mathrm{Z}$$