Whakaoti i te 2^x+4=1/8

$$2 ^ { x + 4 } = \frac { 1 } { 8 }$$

Whakaoti mō x

$$x=-7$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$2^{x+4}=\frac{1}{8}$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(2^{x+4})=\log(\frac{1}{8})$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(x+4\right)\log(2)=\log(\frac{1}{8})$$

Whakawehea ngā taha e rua ki te \log(2).

$$x+4=\frac{\log(\frac{1}{8})}{\log(2)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+4=\log_{2}\left(\frac{1}{8}\right)$$

Me tango 4 mai i ngā taha e rua o te whārite.

$$x=-3-4$$

Whakaoti mō x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(2)}-7$$

$$n_{1}\in \mathrm{Z}$$