Whakaoti i te 2^n-1=1/32

$$2 ^ { n - 1 } = \frac { 1 } { 32 }$$

Whakaoti mō n

$$n=-4$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$2^{n-1}=\frac{1}{32}$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(2^{n-1})=\log(\frac{1}{32})$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(n-1\right)\log(2)=\log(\frac{1}{32})$$

Whakawehea ngā taha e rua ki te \log(2).

$$n-1=\frac{\log(\frac{1}{32})}{\log(2)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$n-1=\log_{2}\left(\frac{1}{32}\right)$$

Me tāpiri 1 ki ngā taha e rua o te whārite.

$$n=-5-\left(-1\right)$$