Whakaoti i te 2^2x+3=8

$$2 ^ { 2 x + 3 } = 8$$

Whakaoti mō x

$$x=0$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$2^{2x+3}=8$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(2^{2x+3})=\log(8)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(2x+3\right)\log(2)=\log(8)$$

Whakawehea ngā taha e rua ki te \log(2).

$$2x+3=\frac{\log(8)}{\log(2)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2x+3=\log_{2}\left(8\right)$$

Me tango 3 mai i ngā taha e rua o te whārite.

$$2x=3-3$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{0}{2}$$

Whakaoti mō x (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(2)}$$

$$n_{1}\in \mathrm{Z}$$