Whakaoti i te 1x+2y=30y*35z

$$1x+2y = 30y \times 35z$$

Whakaoti mō y (complex solution)

$$\left\{\begin{matrix}y=-\frac{x}{2\left(1-525z\right)}\text{, }&z\neq \frac{1}{525}\\y\in \mathrm{C}\text{, }&x=0\text{ and }z=\frac{1}{525}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 30 ki te 35, ka 1050.

$$1x+2y=1050yz$$

Tangohia te 1050yz mai i ngā taha e rua.

$$1x+2y-1050yz=0$$

Tangohia te 1x mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$2y-1050yz=-x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(2-1050z\right)y=-x$$

Whakawehea ngā taha e rua ki te 2-1050z.

$$\frac{\left(2-1050z\right)y}{2-1050z}=-\frac{x}{2-1050z}$$

Mā te whakawehe ki te 2-1050z ka wetekia te whakareanga ki te 2-1050z.

$$y=-\frac{x}{2-1050z}$$

Whakawehe -x ki te 2-1050z.

$$y=-\frac{x}{2\left(1-525z\right)}$$

Whakaoti mō x

$$x=2y\left(525z-1\right)$$

Ngā Upane Otinga

Whakareatia te 30 ki te 35, ka 1050.

$$1x+2y=1050yz$$

Tangohia te 2y mai i ngā taha e rua.

$$1x=1050yz-2y$$

Whakaraupapatia anō ngā kīanga tau.

$$x=1050yz-2y$$

Whakaoti mō y

$$\left\{\begin{matrix}y=-\frac{x}{2\left(1-525z\right)}\text{, }&z\neq \frac{1}{525}\\y\in \mathrm{R}\text{, }&x=0\text{ and }z=\frac{1}{525}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 30 ki te 35, ka 1050.

$$1x+2y=1050yz$$

Tangohia te 1050yz mai i ngā taha e rua.

$$1x+2y-1050yz=0$$

Tangohia te 1x mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$2y-1050yz=-x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(2-1050z\right)y=-x$$

Whakawehea ngā taha e rua ki te 2-1050z.

$$\frac{\left(2-1050z\right)y}{2-1050z}=-\frac{x}{2-1050z}$$

Mā te whakawehe ki te 2-1050z ka wetekia te whakareanga ki te 2-1050z.

$$y=-\frac{x}{2-1050z}$$

Whakawehe -x ki te 2-1050z.

$$y=-\frac{x}{2\left(1-525z\right)}$$