Whakaoti i te 19a^3-12x+4=0

$$19 a ^ { 3 } - 12 x + 4 = 0$$

Whakaoti mō x

$$x=\frac{19a^{3}}{12}+\frac{1}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 19a^{3} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-12x+4=-19a^{3}$$

Tangohia te 4 mai i ngā taha e rua.

$$-12x=-19a^{3}-4$$

Whakawehea ngā taha e rua ki te -12.

$$\frac{-12x}{-12}=\frac{-19a^{3}-4}{-12}$$

Mā te whakawehe ki te -12 ka wetekia te whakareanga ki te -12.

$$x=\frac{-19a^{3}-4}{-12}$$

Whakawehe -19a^{3}-4 ki te -12.

$$x=\frac{19a^{3}}{12}+\frac{1}{3}$$

Whakaoti mō a

$$a=\frac{19^{\frac{2}{3}}\sqrt[3]{12x-4}}{19}$$