Whakaoti i te 18m^2+900=0

$$18 m ^ { 2 } + 900 = 0$$

Whakaoti mō m

$$m=-5\sqrt{2}i\approx -0-7.071067812i$$

$$m=5\sqrt{2}i\approx 7.071067812i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 900 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$18m^{2}=-900$$

Whakawehea ngā taha e rua ki te 18.

$$m^{2}=\frac{-900}{18}$$

Whakawehea te -900 ki te 18, kia riro ko -50.

$$m^{2}=-50$$

Kua oti te whārite te whakatau.

$$m=5\sqrt{2}i m=-5\sqrt{2}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$18m^{2}+900=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 18 mō a, 0 mō b, me 900 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\times 18\times 900}}{2\times 18}$$

Pūrua 0.

$$m=\frac{0±\sqrt{-4\times 18\times 900}}{2\times 18}$$

Whakareatia -4 ki te 18.

$$m=\frac{0±\sqrt{-72\times 900}}{2\times 18}$$

Whakareatia -72 ki te 900.

$$m=\frac{0±\sqrt{-64800}}{2\times 18}$$

Tuhia te pūtakerua o te -64800.

$$m=\frac{0±180\sqrt{2}i}{2\times 18}$$

Whakareatia 2 ki te 18.

$$m=\frac{0±180\sqrt{2}i}{36}$$

Nā, me whakaoti te whārite m=\frac{0±180\sqrt{2}i}{36} ina he tāpiri te ±.

$$m=5\sqrt{2}i$$

Nā, me whakaoti te whārite m=\frac{0±180\sqrt{2}i}{36} ina he tango te ±.

$$m=-5\sqrt{2}i$$

Kua oti te whārite te whakatau.

$$m=5\sqrt{2}i m=-5\sqrt{2}i$$