Whakaoti i te 18(2x/9+1/3)-12(5x/6-1/4)=

$$18 ( \frac { 2 x } { 9 } + \frac { 1 } { 3 } ) - 12 ( \frac { 5 x } { 6 } - \frac { 1 } { 4 } ) =$$

Aromātai

$$9-6x$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 9 me 3 ko 9. Whakareatia \frac{1}{3} ki te \frac{3}{3}.

$$18\left(\frac{2x}{9}+\frac{3}{9}\right)-12\left(\frac{5x}{6}-\frac{1}{4}\right)$$

Tā te mea he rite te tauraro o \frac{2x}{9} me \frac{3}{9}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$18\times \frac{2x+3}{9}-12\left(\frac{5x}{6}-\frac{1}{4}\right)$$

Whakakorea atu te tauwehe pūnoa nui rawa 9 i roto i te 18 me te 9.

$$2\left(2x+3\right)-12\left(\frac{5x}{6}-\frac{1}{4}\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 6 me 4 ko 12. Whakareatia \frac{5x}{6} ki te \frac{2}{2}. Whakareatia \frac{1}{4} ki te \frac{3}{3}.

$$2\left(2x+3\right)-12\left(\frac{2\times 5x}{12}-\frac{3}{12}\right)$$

Tā te mea he rite te tauraro o \frac{2\times 5x}{12} me \frac{3}{12}, me tango rāua mā te tango i ō raua taurunga.

$$2\left(2x+3\right)-12\times \frac{2\times 5x-3}{12}$$

Mahia ngā whakarea i roto o 2\times 5x-3.

$$2\left(2x+3\right)-12\times \frac{10x-3}{12}$$

Me whakakore te 12 me te 12.

$$2\left(2x+3\right)-\left(10x-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 2x+3.

$$4x+6-\left(10x-3\right)$$

Hei kimi i te tauaro o 10x-3, kimihia te tauaro o ia taurangi.

$$4x+6-10x-\left(-3\right)$$

Ko te tauaro o -3 ko 3.

$$4x+6-10x+3$$

Pahekotia te 4x me -10x, ka -6x.

$$-6x+6+3$$

Tāpirihia te 6 ki te 3, ka 9.

$$-6x+9$$

Whakaroha

$$9-6x$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 9 me 3 ko 9. Whakareatia \frac{1}{3} ki te \frac{3}{3}.

$$18\left(\frac{2x}{9}+\frac{3}{9}\right)-12\left(\frac{5x}{6}-\frac{1}{4}\right)$$

Tā te mea he rite te tauraro o \frac{2x}{9} me \frac{3}{9}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$18\times \frac{2x+3}{9}-12\left(\frac{5x}{6}-\frac{1}{4}\right)$$

Whakakorea atu te tauwehe pūnoa nui rawa 9 i roto i te 18 me te 9.

$$2\left(2x+3\right)-12\left(\frac{5x}{6}-\frac{1}{4}\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 6 me 4 ko 12. Whakareatia \frac{5x}{6} ki te \frac{2}{2}. Whakareatia \frac{1}{4} ki te \frac{3}{3}.

$$2\left(2x+3\right)-12\left(\frac{2\times 5x}{12}-\frac{3}{12}\right)$$

Tā te mea he rite te tauraro o \frac{2\times 5x}{12} me \frac{3}{12}, me tango rāua mā te tango i ō raua taurunga.

$$2\left(2x+3\right)-12\times \frac{2\times 5x-3}{12}$$

Mahia ngā whakarea i roto o 2\times 5x-3.

$$2\left(2x+3\right)-12\times \frac{10x-3}{12}$$

Me whakakore te 12 me te 12.

$$2\left(2x+3\right)-\left(10x-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 2x+3.

$$4x+6-\left(10x-3\right)$$

Hei kimi i te tauaro o 10x-3, kimihia te tauaro o ia taurangi.

$$4x+6-10x-\left(-3\right)$$

Ko te tauaro o -3 ko 3.

$$4x+6-10x+3$$

Pahekotia te 4x me -10x, ka -6x.

$$-6x+6+3$$

Tāpirihia te 6 ki te 3, ka 9.

$$-6x+9$$