Whakaoti i te 18^2-5x+sqrt{5}=x

$$18 ^ { 2 } - 5 x + \sqrt { 5 } = x$$

Whakaoti mō x

$$x = \frac{\sqrt{5} + 324}{6} \approx 54.372677996$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$324-5x+\sqrt{5}=x$$

Tangohia te x mai i ngā taha e rua.

$$324-5x+\sqrt{5}-x=0$$

Pahekotia te -5x me -x, ka -6x.

$$324-6x+\sqrt{5}=0$$

Tangohia te 324 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-6x+\sqrt{5}=-324$$

Tangohia te \sqrt{5} mai i ngā taha e rua.

$$-6x=-324-\sqrt{5}$$

He hanga arowhānui tō te whārite.

$$-6x=-\sqrt{5}-324$$

Whakawehea ngā taha e rua ki te -6.

$$\frac{-6x}{-6}=\frac{-\sqrt{5}-324}{-6}$$

Mā te whakawehe ki te -6 ka wetekia te whakareanga ki te -6.

$$x=\frac{-\sqrt{5}-324}{-6}$$

Whakawehe -324-\sqrt{5} ki te -6.

$$x=\frac{\sqrt{5}}{6}+54$$