Whakaoti i te 18+y^2=9

$$18 + y ^ { 2 } = 9$$

Whakaoti mō y

$$y=-3i$$

$$y=3i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 18 mai i ngā taha e rua.

$$y^{2}=9-18$$

Tangohia te 18 i te 9, ka -9.

$$y^{2}=-9$$

Kua oti te whārite te whakatau.

$$y=3i y=-3i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 9 mai i ngā taha e rua.

$$18+y^{2}-9=0$$

Tangohia te 9 i te 18, ka 9.

$$9+y^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$y^{2}+9=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 9 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\times 9}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\times 9}}{2}$$

Whakareatia -4 ki te 9.

$$y=\frac{0±\sqrt{-36}}{2}$$

Tuhia te pūtakerua o te -36.

$$y=\frac{0±6i}{2}$$

Nā, me whakaoti te whārite y=\frac{0±6i}{2} ina he tāpiri te ±.

$$y=3i$$

Nā, me whakaoti te whārite y=\frac{0±6i}{2} ina he tango te ±.

$$y=-3i$$

Kua oti te whārite te whakatau.

$$y=3i y=-3i$$