Whakaoti i te 16+x^2=left(8-xright)^2

$$16+ { x }^{ 2 } = { \left(8-x \right) }^{ 2 }$$

Whakaoti mō x

$$x=3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(8-x\right)^{2}.

$$16+x^{2}=64-16x+x^{2}$$

Me tāpiri te 16x ki ngā taha e rua.

$$16+x^{2}+16x=64+x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$16+x^{2}+16x-x^{2}=64$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$16+16x=64$$

Tangohia te 16 mai i ngā taha e rua.

$$16x=64-16$$

Tangohia te 16 i te 64, ka 48.

$$16x=48$$

Whakawehea ngā taha e rua ki te 16.

$$x=\frac{48}{16}$$

Whakawehea te 48 ki te 16, kia riro ko 3.

$$x=3$$