Whakaoti i te 16-y^4

$$16 - y ^ { 4 }$$

Tauwehe

$$\left(y-2\right)\left(y+2\right)\left(-y^{2}-4\right)$$

Ngā Upane Otinga

Tuhia anō te 16-y^{4} hei 4^{2}-\left(-y^{2}\right)^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(4+y^{2}\right)\left(4-y^{2}\right)$$

Whakaraupapatia anō ngā kīanga tau.

$$\left(y^{2}+4\right)\left(-y^{2}+4\right)$$

Whakaarohia te -y^{2}+4. Tuhia anō te -y^{2}+4 hei 2^{2}-y^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(2-y\right)\left(2+y\right)$$

Whakaraupapatia anō ngā kīanga tau.

$$\left(-y+2\right)\left(y+2\right)$$

Me tuhi anō te kīanga whakatauwehe katoa. Kāore te pūrau y^{2}+4 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$\left(-y+2\right)\left(y+2\right)\left(y^{2}+4\right)$$

Aromātai

$$16-y^{4}$$