Whakaoti i te 15x^2-20x+10=

$$15 x ^ { 2 } - 20 x + 10 =$$

Tauwehe

$$5\left(3x^{2}-4x+2\right)$$

Ngā Upane Otinga

Tauwehea te 5. Kāore te pūrau 3x^{2}-4x+2 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$5\left(3x^{2}-4x+2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$15x^{2}-20x+10=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-20\right)±\sqrt{\left(-20\right)^{2}-4\times 15\times 10}}{2\times 15}$$

Pūrua -20.

$$x=\frac{-\left(-20\right)±\sqrt{400-4\times 15\times 10}}{2\times 15}$$

Whakareatia -4 ki te 15.

$$x=\frac{-\left(-20\right)±\sqrt{400-60\times 10}}{2\times 15}$$

Whakareatia -60 ki te 10.

$$x=\frac{-\left(-20\right)±\sqrt{400-600}}{2\times 15}$$

Tāpiri 400 ki te -600.

$$x=\frac{-\left(-20\right)±\sqrt{-200}}{2\times 15}$$

Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. Kāore e taea te pūrau pūrua te whakatauwehe.

$$15x^{2}-20x+10$$

Aromātai

$$15x^{2}-20x+10$$