Whakaoti mō x
x = \frac{\log_{15} {(506250)}}{3} \approx 1.616758051
Whakaoti mō x (complex solution)
x=\frac{2\pi n_{1}i}{3\ln(15)}+\frac{\log_{15}\left(506250\right)}{3}
n_{1}\in \mathrm{Z}
Graph
Tohaina
Kua tāruatia ki te papatopenga
15^{3x-4}=10
Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.
\log(15^{3x-4})=\log(10)
Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.
\left(3x-4\right)\log(15)=\log(10)
Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.
3x-4=\frac{\log(10)}{\log(15)}
Whakawehea ngā taha e rua ki te \log(15).
3x-4=\log_{15}\left(10\right)
Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3x=\log_{15}\left(10\right)-\left(-4\right)
Me tāpiri 4 ki ngā taha e rua o te whārite.
x=\frac{\log_{15}\left(10\right)+4}{3}
Whakawehea ngā taha e rua ki te 3.
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