Whakaoti i te 15^2=5^2+c^2

$$15 ^ { 2 } = 5 ^ { 2 } + c ^ { 2 }$$

Whakaoti mō c

$$c=10\sqrt{2}\approx 14.142135624$$

$$c=-10\sqrt{2}\approx -14.142135624$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$225=5^{2}+c^{2}$$

Tātaihia te 5 mā te pū o 2, kia riro ko 25.

$$225=25+c^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$25+c^{2}=225$$

Tangohia te 25 mai i ngā taha e rua.

$$c^{2}=225-25$$

Tangohia te 25 i te 225, ka 200.

$$c^{2}=200$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$c=10\sqrt{2} c=-10\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$225=5^{2}+c^{2}$$

Tātaihia te 5 mā te pū o 2, kia riro ko 25.

$$225=25+c^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$25+c^{2}=225$$

Tangohia te 225 mai i ngā taha e rua.

$$25+c^{2}-225=0$$

Tangohia te 225 i te 25, ka -200.

$$-200+c^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$c^{2}-200=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -200 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$c=\frac{0±\sqrt{0^{2}-4\left(-200\right)}}{2}$$

Pūrua 0.

$$c=\frac{0±\sqrt{-4\left(-200\right)}}{2}$$

Whakareatia -4 ki te -200.

$$c=\frac{0±\sqrt{800}}{2}$$

Tuhia te pūtakerua o te 800.

$$c=\frac{0±20\sqrt{2}}{2}$$

Nā, me whakaoti te whārite c=\frac{0±20\sqrt{2}}{2} ina he tāpiri te ±.

$$c=10\sqrt{2}$$

Nā, me whakaoti te whārite c=\frac{0±20\sqrt{2}}{2} ina he tango te ±.

$$c=-10\sqrt{2}$$

Kua oti te whārite te whakatau.

$$c=10\sqrt{2} c=-10\sqrt{2}$$