Whakaoti i te 14-(6-x)*(6-x)=x(2-x)

$$14-(6-x) \times (6-x)=x(2-x)$$

Whakaoti mō x

$$x = \frac{11}{5} = 2\frac{1}{5} = 2.2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 6-x ki te 6-x, ka \left(6-x\right)^{2}.

$$14-\left(6-x\right)^{2}=x\left(2-x\right)$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(6-x\right)^{2}.

$$14-\left(36-12x+x^{2}\right)=x\left(2-x\right)$$

Hei kimi i te tauaro o 36-12x+x^{2}, kimihia te tauaro o ia taurangi.

$$14-36+12x-x^{2}=x\left(2-x\right)$$

Tangohia te 36 i te 14, ka -22.

$$-22+12x-x^{2}=x\left(2-x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 2-x.

$$-22+12x-x^{2}=2x-x^{2}$$

Tangohia te 2x mai i ngā taha e rua.

$$-22+12x-x^{2}-2x=-x^{2}$$

Pahekotia te 12x me -2x, ka 10x.

$$-22+10x-x^{2}=-x^{2}$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$-22+10x-x^{2}+x^{2}=0$$

Pahekotia te -x^{2} me x^{2}, ka 0.

$$-22+10x=0$$

Me tāpiri te 22 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$10x=22$$

Whakawehea ngā taha e rua ki te 10.

$$x=\frac{22}{10}$$

Whakahekea te hautanga \frac{22}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{11}{5}$$