Whakaoti i te 13698F_{1}=9-x/x

$$13698 F _ { 1 } = \frac { 9 - x } { x }$$

Whakaoti mō F_1

$$F_{1}=-\frac{1}{13698}+\frac{1}{1522x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te x.

$$13698F_{1}x=9-x$$

He hanga arowhānui tō te whārite.

$$13698xF_{1}=9-x$$

Whakawehea ngā taha e rua ki te 13698x.

$$\frac{13698xF_{1}}{13698x}=\frac{9-x}{13698x}$$

Mā te whakawehe ki te 13698x ka wetekia te whakareanga ki te 13698x.

$$F_{1}=\frac{9-x}{13698x}$$

Whakawehe 9-x ki te 13698x.

$$F_{1}=-\frac{1}{13698}+\frac{1}{1522x}$$

Whakaoti mō x

$$x=\frac{9}{13698F_{1}+1}$$

$$F_{1}\neq -\frac{1}{13698}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$13698F_{1}x=9-x$$

Me tāpiri te x ki ngā taha e rua.

$$13698F_{1}x+x=9$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(13698F_{1}+1\right)x=9$$

Whakawehea ngā taha e rua ki te 13698F_{1}+1.

$$\frac{\left(13698F_{1}+1\right)x}{13698F_{1}+1}=\frac{9}{13698F_{1}+1}$$

Mā te whakawehe ki te 13698F_{1}+1 ka wetekia te whakareanga ki te 13698F_{1}+1.

$$x=\frac{9}{13698F_{1}+1}$$

Tē taea kia ōrite te tāupe x ki 0.

$$x=\frac{9}{13698F_{1}+1}\text{, }x\neq 0$$