Whakaoti i te 13x^2=-4

$$13 x ^ { 2 } = - 4$$

Whakaoti mō x (complex solution)

$$x=-\frac{2\sqrt{13}i}{13}\approx -0-0.554700196i$$

$$x=\frac{2\sqrt{13}i}{13}\approx 0.554700196i$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 13.

$$x^{2}=-\frac{4}{13}$$

Kua oti te whārite te whakatau.

$$x=\frac{2\sqrt{13}i}{13} x=-\frac{2\sqrt{13}i}{13}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 13.

$$x^{2}=-\frac{4}{13}$$

Me tāpiri te \frac{4}{13} ki ngā taha e rua.

$$x^{2}+\frac{4}{13}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me \frac{4}{13} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times \frac{4}{13}}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times \frac{4}{13}}}{2}$$

Whakareatia -4 ki te \frac{4}{13}.

$$x=\frac{0±\sqrt{-\frac{16}{13}}}{2}$$

Tuhia te pūtakerua o te -\frac{16}{13}.

$$x=\frac{0±\frac{4\sqrt{13}i}{13}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{4\sqrt{13}i}{13}}{2} ina he tāpiri te ±.

$$x=\frac{2\sqrt{13}i}{13}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{4\sqrt{13}i}{13}}{2} ina he tango te ±.

$$x=-\frac{2\sqrt{13}i}{13}$$

Kua oti te whārite te whakatau.

$$x=\frac{2\sqrt{13}i}{13} x=-\frac{2\sqrt{13}i}{13}$$