Whakaoti i te 13m+15m^2

$$13 m + 15 m ^ { 2 }$$

Tauwehe

$$m\left(15m+13\right)$$

Ngā Upane Otinga

Tauwehea te m.

$$m\left(13+15m\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$15m^{2}+13m=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$m=\frac{-13±\sqrt{13^{2}}}{2\times 15}$$

Tuhia te pūtakerua o te 13^{2}.

$$m=\frac{-13±13}{2\times 15}$$

Whakareatia 2 ki te 15.

$$m=\frac{-13±13}{30}$$

Nā, me whakaoti te whārite m=\frac{-13±13}{30} ina he tāpiri te ±. Tāpiri -13 ki te 13.

$$m=\frac{0}{30}$$

Whakawehe 0 ki te 30.

$$m=0$$

Nā, me whakaoti te whārite m=\frac{-13±13}{30} ina he tango te ±. Tango 13 mai i -13.

$$m=-\frac{26}{30}$$

Whakahekea te hautanga \frac{-26}{30} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$m=-\frac{13}{15}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te -\frac{13}{15} mō te x_{2}.

$$15m^{2}+13m=15m\left(m-\left(-\frac{13}{15}\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$15m^{2}+13m=15m\left(m+\frac{13}{15}\right)$$

Tāpiri \frac{13}{15} ki te m mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$15m^{2}+13m=15m\times \frac{15m+13}{15}$$

Whakakorea atu te tauwehe pūnoa nui rawa 15 i roto i te 15 me te 15.

$$15m^{2}+13m=m\left(15m+13\right)$$

Aromātai

$$m\left(15m+13\right)$$