Whakaoti i te 13-4x^2>0

$$13 - 4 x ^ { 2 } > 0$$

Whakaoti mō x

$$x\in \left(-\frac{\sqrt{13}}{2},\frac{\sqrt{13}}{2}\right)$$

Ngā Upane Otinga

Me whakarea te koreōrite ki te -1 kia tōrunga ai te tau whakarea o te pū tino teitei i 13-4x^{2}. I te mea he tōraro a -1, ka huri te ahunga koreōrite.

$$-13+4x^{2}<0$$

Me tāpiri te \frac{13}{4} ki ngā taha e rua.

$$x^{2}<\frac{13}{4}$$

Tātaitia te pūtakerua o \frac{13}{4} kia tae ki \frac{\sqrt{13}}{2}. Tuhia anō te \frac{13}{4} hei \left(\frac{\sqrt{13}}{2}\right)^{2}.

$$x^{2}<\left(\frac{\sqrt{13}}{2}\right)^{2}$$

E mau ana te koreōrite mō |x|<\frac{\sqrt{13}}{2}.

$$|x|<\frac{\sqrt{13}}{2}$$

Tuhia anō te |x|<\frac{\sqrt{13}}{2} hei x\in \left(-\frac{\sqrt{13}}{2},\frac{\sqrt{13}}{2}\right).

$$x\in \left(-\frac{\sqrt{13}}{2},\frac{\sqrt{13}}{2}\right)$$