Whakaoti i te 125x^2+2x

$$125 x ^ { 2 } + 2 x$$

Tauwehe

$$x\left(125x+2\right)$$

Ngā Upane Otinga

Tauwehea te x.

$$x\left(125x+2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$125x^{2}+2x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-2±\sqrt{2^{2}}}{2\times 125}$$

Tuhia te pūtakerua o te 2^{2}.

$$x=\frac{-2±2}{2\times 125}$$

Whakareatia 2 ki te 125.

$$x=\frac{-2±2}{250}$$

Nā, me whakaoti te whārite x=\frac{-2±2}{250} ina he tāpiri te ±. Tāpiri -2 ki te 2.

$$x=\frac{0}{250}$$

Whakawehe 0 ki te 250.

$$x=0$$

Nā, me whakaoti te whārite x=\frac{-2±2}{250} ina he tango te ±. Tango 2 mai i -2.

$$x=-\frac{4}{250}$$

Whakahekea te hautanga \frac{-4}{250} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=-\frac{2}{125}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te -\frac{2}{125} mō te x_{2}.

$$125x^{2}+2x=125x\left(x-\left(-\frac{2}{125}\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$125x^{2}+2x=125x\left(x+\frac{2}{125}\right)$$

Tāpiri \frac{2}{125} ki te x mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$125x^{2}+2x=125x\times \frac{125x+2}{125}$$

Whakakorea atu te tauwehe pūnoa nui rawa 125 i roto i te 125 me te 125.

$$125x^{2}+2x=x\left(125x+2\right)$$

Aromātai

$$x\left(125x+2\right)$$