Whakaoti i te 12-x(2x+1)=3x-2x^2+7

$$12-x(2x+1)=3x-2 { x }^{ 2 } +7$$

Whakaoti mō x

$$x = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 2x+1.

$$12-\left(2x^{2}+x\right)=3x-2x^{2}+7$$

Hei kimi i te tauaro o 2x^{2}+x, kimihia te tauaro o ia taurangi.

$$12-2x^{2}-x=3x-2x^{2}+7$$

Tangohia te 3x mai i ngā taha e rua.

$$12-2x^{2}-x-3x=-2x^{2}+7$$

Pahekotia te -x me -3x, ka -4x.

$$12-2x^{2}-4x=-2x^{2}+7$$

Me tāpiri te 2x^{2} ki ngā taha e rua.

$$12-2x^{2}-4x+2x^{2}=7$$

Pahekotia te -2x^{2} me 2x^{2}, ka 0.

$$12-4x=7$$

Tangohia te 12 mai i ngā taha e rua.

$$-4x=7-12$$

Tangohia te 12 i te 7, ka -5.

$$-4x=-5$$

Whakawehea ngā taha e rua ki te -4.

$$x=\frac{-5}{-4}$$

Ka taea te hautanga \frac{-5}{-4} te whakamāmā ki te \frac{5}{4} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{5}{4}$$