Whakaoti i te 12-2x^2=-16

$$12 - 2 x ^ { 2 } = - 16$$

Whakaoti mō x

$$x=\sqrt{14}\approx 3.741657387$$

$$x=-\sqrt{14}\approx -3.741657387$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 12 mai i ngā taha e rua.

$$-2x^{2}=-16-12$$

Tangohia te 12 i te -16, ka -28.

$$-2x^{2}=-28$$

Whakawehea ngā taha e rua ki te -2.

$$x^{2}=\frac{-28}{-2}$$

Whakawehea te -28 ki te -2, kia riro ko 14.

$$x^{2}=14$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{14} x=-\sqrt{14}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 16 ki ngā taha e rua.

$$12-2x^{2}+16=0$$

Tāpirihia te 12 ki te 16, ka 28.

$$28-2x^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-2x^{2}+28=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -2 mō a, 0 mō b, me 28 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2\right)\times 28}}{2\left(-2\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-2\right)\times 28}}{2\left(-2\right)}$$

Whakareatia -4 ki te -2.

$$x=\frac{0±\sqrt{8\times 28}}{2\left(-2\right)}$$

Whakareatia 8 ki te 28.

$$x=\frac{0±\sqrt{224}}{2\left(-2\right)}$$

Tuhia te pūtakerua o te 224.

$$x=\frac{0±4\sqrt{14}}{2\left(-2\right)}$$

Whakareatia 2 ki te -2.

$$x=\frac{0±4\sqrt{14}}{-4}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{14}}{-4} ina he tāpiri te ±.

$$x=-\sqrt{14}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{14}}{-4} ina he tango te ±.

$$x=\sqrt{14}$$

Kua oti te whārite te whakatau.

$$x=-\sqrt{14} x=\sqrt{14}$$