Whakaoti i te 12x^2+10=23

$$12 { x }^{ 2 } +10=23$$

Whakaoti mō x

$$x = \frac{\sqrt{39}}{6} \approx 1.040833$$

$$x = -\frac{\sqrt{39}}{6} \approx -1.040833$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 10 mai i ngā taha e rua.

$$12x^{2}=23-10$$

Tangohia te 10 i te 23, ka 13.

$$12x^{2}=13$$

Whakawehea ngā taha e rua ki te 12.

$$x^{2}=\frac{13}{12}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{39}}{6} x=-\frac{\sqrt{39}}{6}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 23 mai i ngā taha e rua.

$$12x^{2}+10-23=0$$

Tangohia te 23 i te 10, ka -13.

$$12x^{2}-13=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 12 mō a, 0 mō b, me -13 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 12\left(-13\right)}}{2\times 12}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 12\left(-13\right)}}{2\times 12}$$

Whakareatia -4 ki te 12.

$$x=\frac{0±\sqrt{-48\left(-13\right)}}{2\times 12}$$

Whakareatia -48 ki te -13.

$$x=\frac{0±\sqrt{624}}{2\times 12}$$

Tuhia te pūtakerua o te 624.

$$x=\frac{0±4\sqrt{39}}{2\times 12}$$

Whakareatia 2 ki te 12.

$$x=\frac{0±4\sqrt{39}}{24}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{39}}{24} ina he tāpiri te ±.

$$x=\frac{\sqrt{39}}{6}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{39}}{24} ina he tango te ±.

$$x=-\frac{\sqrt{39}}{6}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{39}}{6} x=-\frac{\sqrt{39}}{6}$$