Whakaoti i te 11x=9x/5y+13y

$$11x= \frac{ 9x }{ 5y } +13y$$

Whakaoti mō x

$$x=\frac{65y^{2}}{55y-9}$$

$$y\neq \frac{9}{55}\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 5y.

$$11x\times 5y=9x+13y\times 5y$$

Whakareatia te 11 ki te 5, ka 55.

$$55xy=9x+13y\times 5y$$

Whakareatia te y ki te y, ka y^{2}.

$$55xy=9x+13y^{2}\times 5$$

Whakareatia te 13 ki te 5, ka 65.

$$55xy=9x+65y^{2}$$

Tangohia te 9x mai i ngā taha e rua.

$$55xy-9x=65y^{2}$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(55y-9\right)x=65y^{2}$$

Whakawehea ngā taha e rua ki te 55y-9.

$$\frac{\left(55y-9\right)x}{55y-9}=\frac{65y^{2}}{55y-9}$$

Mā te whakawehe ki te 55y-9 ka wetekia te whakareanga ki te 55y-9.

$$x=\frac{65y^{2}}{55y-9}$$

Whakaoti mō y (complex solution)

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\neq 0$$

Whakaoti mō y

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\geq \frac{468}{605}\text{ or }x<0$$