Whakaoti i te 112x^3-3x^2-116x+4

$$112 x ^ { 3 } - 3 x ^ { 2 } - 116 x + 4$$

Kimi Pārōnaki e ai ki x

$$336x^{2}-6x-116$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 112x^{3-1}+2\left(-3\right)x^{2-1}-116x^{1-1}$$

Whakareatia 3 ki te 112.

$$336x^{3-1}+2\left(-3\right)x^{2-1}-116x^{1-1}$$

Tango 1 mai i 3.

$$336x^{2}+2\left(-3\right)x^{2-1}-116x^{1-1}$$

Whakareatia 2 ki te -3.

$$336x^{2}-6x^{2-1}-116x^{1-1}$$

Tango 1 mai i 2.

$$336x^{2}-6x^{1}-116x^{1-1}$$

Tango 1 mai i 1.

$$336x^{2}-6x^{1}-116x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$336x^{2}-6x-116x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$336x^{2}-6x-116$$

Aromātai

$$112x^{3}-3x^{2}-116x+4$$