Whakaoti i te 11=x+13*40/40+x

$$11= \frac{ x+13 \times 40 }{ 40+x }$$

Whakaoti mō x

$$x=8$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki -40 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x+40.

$$11\left(x+40\right)=x+13\times 40$$

Whakamahia te āhuatanga tohatoha hei whakarea te 11 ki te x+40.

$$11x+440=x+13\times 40$$

Whakareatia te 13 ki te 40, ka 520.

$$11x+440=x+520$$

Tangohia te x mai i ngā taha e rua.

$$11x+440-x=520$$

Pahekotia te 11x me -x, ka 10x.

$$10x+440=520$$

Tangohia te 440 mai i ngā taha e rua.

$$10x=520-440$$

Tangohia te 440 i te 520, ka 80.

$$10x=80$$

Whakawehea ngā taha e rua ki te 10.

$$x=\frac{80}{10}$$

Whakawehea te 80 ki te 10, kia riro ko 8.

$$x=8$$