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Whakaoti mō x
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Tohaina

x-\frac{1}{5}=\frac{1}{5}+\frac{2}{5}
Pahekotia te 11x me -10x, ka x.
x-\frac{1}{5}=\frac{1+2}{5}
Tā te mea he rite te tauraro o \frac{1}{5} me \frac{2}{5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.
x-\frac{1}{5}=\frac{3}{5}
Tāpirihia te 1 ki te 2, ka 3.
x=\frac{3}{5}+\frac{1}{5}
Me tāpiri te \frac{1}{5} ki ngā taha e rua.
x=\frac{3+1}{5}
Tā te mea he rite te tauraro o \frac{3}{5} me \frac{1}{5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.
x=\frac{4}{5}
Tāpirihia te 3 ki te 1, ka 4.