Whakaoti i te 10000cm^2=2pi(25)^2+2pi(25)h

$$10000 cm ^ { 2 } = 2 \pi ( 25 ) ^ { 2 } + 2 \pi ( 25 ) h$$

Whakaoti mō c (complex solution)

$$\left\{\begin{matrix}c=\frac{\pi \left(h+25\right)}{200m^{2}}\text{, }&m\neq 0\\c\in \mathrm{C}\text{, }&h=-25\text{ and }m=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 25 mā te pū o 2, kia riro ko 625.

$$10000cm^{2}=2\pi \times 625+2\pi \times 25h$$

Whakareatia te 2 ki te 625, ka 1250.

$$10000cm^{2}=1250\pi +2\pi \times 25h$$

Whakareatia te 2 ki te 25, ka 50.

$$10000cm^{2}=1250\pi +50\pi h$$

He hanga arowhānui tō te whārite.

$$10000m^{2}c=50\pi h+1250\pi$$

Whakawehea ngā taha e rua ki te 10000m^{2}.

$$\frac{10000m^{2}c}{10000m^{2}}=\frac{50\pi \left(h+25\right)}{10000m^{2}}$$

Mā te whakawehe ki te 10000m^{2} ka wetekia te whakareanga ki te 10000m^{2}.

$$c=\frac{50\pi \left(h+25\right)}{10000m^{2}}$$

Whakawehe 50\pi \left(25+h\right) ki te 10000m^{2}.

$$c=\frac{\pi \left(h+25\right)}{200m^{2}}$$

Whakaoti mō c

$$\left\{\begin{matrix}c=\frac{\pi \left(h+25\right)}{200m^{2}}\text{, }&m\neq 0\\c\in \mathrm{R}\text{, }&h=-25\text{ and }m=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 25 mā te pū o 2, kia riro ko 625.

$$10000cm^{2}=2\pi \times 625+2\pi \times 25h$$

Whakareatia te 2 ki te 625, ka 1250.

$$10000cm^{2}=1250\pi +2\pi \times 25h$$

Whakareatia te 2 ki te 25, ka 50.

$$10000cm^{2}=1250\pi +50\pi h$$

He hanga arowhānui tō te whārite.

$$10000m^{2}c=50\pi h+1250\pi$$

Whakawehea ngā taha e rua ki te 10000m^{2}.

$$\frac{10000m^{2}c}{10000m^{2}}=\frac{50\pi \left(h+25\right)}{10000m^{2}}$$

Mā te whakawehe ki te 10000m^{2} ka wetekia te whakareanga ki te 10000m^{2}.

$$c=\frac{50\pi \left(h+25\right)}{10000m^{2}}$$

Whakawehe 50\pi \left(25+h\right) ki te 10000m^{2}.

$$c=\frac{\pi \left(h+25\right)}{200m^{2}}$$

Whakaoti mō h

$$h=\frac{200cm^{2}}{\pi }-25$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 25 mā te pū o 2, kia riro ko 625.

$$10000cm^{2}=2\pi \times 625+2\pi \times 25h$$

Whakareatia te 2 ki te 625, ka 1250.

$$10000cm^{2}=1250\pi +2\pi \times 25h$$

Whakareatia te 2 ki te 25, ka 50.

$$10000cm^{2}=1250\pi +50\pi h$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$1250\pi +50\pi h=10000cm^{2}$$

Tangohia te 1250\pi mai i ngā taha e rua.

$$50\pi h=10000cm^{2}-1250\pi$$

Whakawehea ngā taha e rua ki te 50\pi .

$$\frac{50\pi h}{50\pi }=\frac{10000cm^{2}-1250\pi }{50\pi }$$

Mā te whakawehe ki te 50\pi ka wetekia te whakareanga ki te 50\pi .

$$h=\frac{10000cm^{2}-1250\pi }{50\pi }$$

Whakawehe 10000cm^{2}-1250\pi ki te 50\pi .

$$h=\frac{200cm^{2}}{\pi }-25$$