Whakaoti i te 1000^2+p^2=100

$$1000 ^ { 2 } + p ^ { 2 } = 100$$

Whakaoti mō p

$$p=-30\sqrt{1111}i\approx -0-999.94999875i$$

$$p=30\sqrt{1111}i\approx 999.94999875i$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 1000 mā te pū o 2, kia riro ko 1000000.

$$1000000+p^{2}=100$$

Tangohia te 1000000 mai i ngā taha e rua.

$$p^{2}=100-1000000$$

Tangohia te 1000000 i te 100, ka -999900.

$$p^{2}=-999900$$

Kua oti te whārite te whakatau.

$$p=30\sqrt{1111}i p=-30\sqrt{1111}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 1000 mā te pū o 2, kia riro ko 1000000.

$$1000000+p^{2}=100$$

Tangohia te 100 mai i ngā taha e rua.

$$1000000+p^{2}-100=0$$

Tangohia te 100 i te 1000000, ka 999900.

$$999900+p^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$p^{2}+999900=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 999900 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$p=\frac{0±\sqrt{0^{2}-4\times 999900}}{2}$$

Pūrua 0.

$$p=\frac{0±\sqrt{-4\times 999900}}{2}$$

Whakareatia -4 ki te 999900.

$$p=\frac{0±\sqrt{-3999600}}{2}$$

Tuhia te pūtakerua o te -3999600.

$$p=\frac{0±60\sqrt{1111}i}{2}$$

Nā, me whakaoti te whārite p=\frac{0±60\sqrt{1111}i}{2} ina he tāpiri te ±.

$$p=30\sqrt{1111}i$$

Nā, me whakaoti te whārite p=\frac{0±60\sqrt{1111}i}{2} ina he tango te ±.

$$p=-30\sqrt{1111}i$$

Kua oti te whārite te whakatau.

$$p=30\sqrt{1111}i p=-30\sqrt{1111}i$$